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2.88x^2-16.14x+1=0
a = 2.88; b = -16.14; c = +1;
Δ = b2-4ac
Δ = -16.142-4·2.88·1
Δ = 248.9796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16.14)-\sqrt{248.9796}}{2*2.88}=\frac{16.14-\sqrt{248.9796}}{5.76} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16.14)+\sqrt{248.9796}}{2*2.88}=\frac{16.14+\sqrt{248.9796}}{5.76} $
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